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Recommendation for solving leakage current on 10250T/E24/M22 pilot devices LED bulbs

A 10kΩ 5W resistor in series with the light typically does the trick.  You could also check how much leakage current you have in the lines and do the math below.

Determine proper ohmic value for the resistor: RN = 120 / IL, where RN is the resistor needed, 120 is the applied voltage, and IL is the leakage current from the PLC specs.

Determine the minimum wattage rating for the resistor: W = IL squared x RN.